A) \[10\,J/s\]
B) \[4\pi /3\,\,J/s\]
C) \[2\pi /3\,\,J/s\]
D) 0
Correct Answer: D
Solution :
Time period of oscillation \[T=\frac{2\pi }{\omega }=\frac{2\pi }{2\pi }=1\sec .\] Hence, t = 1.25 sec, that is, at T/4 seconds after t = 1 second, the particle is at rest at extreme position. Hence instantaneous power at x = 2 at t = 1.25 sec is zero.You need to login to perform this action.
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