question_answer

A particle moves along x-axis with initial position \[x=0.\] Its velocity varies with x-coordinate as shown in graph. The acceleration 'a' of this particle varies with x as

A)                                           

B)  

C)                                           

D)              

Correct Answer: A

Solution :

 The linear relationship between v and x is v =-mx+C where m and C are positive constants.               \[\therefore \]Acceleration, \[a=v\frac{dv}{dx}=-m(-mx+C)\] \[\therefore \]a = m2x - mC Hence the graph relating a to x is