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JEE Main & Advanced Sample Paper JEE Main Sample Paper-6

  • question_answer
    Directions: Question No. 64 are based on the following paragraph. Mixture of organic compounds can be separated into individual components based on the solubility in different reagents, for example an acidic compound can be extracted into NaOH solution and a basic compound into HCl solution. Mixtures have been formed from the following compounds. A:naphthalene                  B: p-dichlorobenzend C: aniline                              D: phenol E: benzoic acid                   F: \[C{{H}_{3}}OH\] G: \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}N{{H}_{2}}\]                H: \[\text{C}{{\text{H}}_{\text{3}}}\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\mathop{\text{C}}}\,\text{HC}{{\text{H}}_{\text{3}}}\] Answer the questions based on the above compounds. Distinction between F and H can be made by

    A)  Iodoform test                  

    B)  Carbylamine test

    C)  Phthalein test

    D)  Ceric ammonium nitrate

    Correct Answer: A

    Solution :

    The compounds containing \[-COC{{H}_{3}}\]group or \[-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-\text{C}{{\text{H}}_{\text{3}}}\]group shows positive iodoform test. In between \[FC{{H}_{3}}OH\] and H\[\left( C{{H}_{3}}-\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-C{{H}_{3}} \right),\]only   H   contains \[\left( -\underset{\begin{smallmatrix}  \text{ }\!\!|\!\!\text{ } \\  \text{OH} \end{smallmatrix}}{\mathop{\text{CH}}}\,-C{{H}_{3}} \right)\] group. Thus, it gives positive iodoform test. Hence, F and H are distinguish by iodoform test.


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