A) 100 keV
B) 90 keV
C) 110 keV
D) None of these
Correct Answer: C
Solution :
\[{{E}_{K}}-{{E}_{M}}=\frac{1242}{12.42}keV=100keV\] [Energy for \[{{K}_{\beta }}X-ray\]] [Energy required to take the \[{{e}^{-1}}\] from M shell to infinity] So, \[{{E}_{K}}-0=10keV\] [Here, we are considering only the values without sign]You need to login to perform this action.
You will be redirected in
3 sec