A) \[1.5\times {{10}^{-18}}Joule\]
B) \[1.5\times {{10}^{-14}}Joule\]
C) \[1.5\times {{10}^{-12}}Joule\]
D) \[1.5\times {{10}^{-10}}Joule\]
Correct Answer: D
Solution :
\[E=\Delta m{{c}^{2}}\] \[=931.5MeV\] \[=931.5\times {{10}^{5}}\times 1.6\times {{10}^{-19}}J\] \[=1.5\times {{10}^{-10}}J\]
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