| Direction: According to the 6ohr model, the energy levels of a hydrogen atom can be found by making two assumptions. |
| (i) The electrons move in a circular orbit and (ii) the angular momentum of the electron in the n\[th\]energy level is quantized to have a value,\[n\frac{h}{2\pi }\]. The levels calculated with a nuclear charge \[Ze\] deals with a single electron in the orbit are called hydrogenic levels. Assume that the two electrons in the ground, state of a helium atom occupy the corresponding lowest hydrogenic level. |
A) 3.4 eV
B) 6.8 eV
C) 13.6eV
D) 27.2eV
Correct Answer: D
Solution :
As, \[U=2E\] \[\Rightarrow \] \[\frac{-k(Z{{e}^{2}})}{r}=2\,(-54.4)\] \[\Rightarrow \] \[\frac{k{{e}^{2}}}{r}=54.4\,eV\] Minimum repulsive energy between the two electrons \[=\frac{k{{e}^{2}}}{2r}=\frac{54.4}{2}=27.2\,eV\]
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