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JEE Main & Advanced Sample Paper JEE Main Sample Paper-44

  • question_answer
    If the input and output resistances in a common-base amplifier circuit are \[400\,\,\Omega \] and \[400\,\,k\,\Omega ,\] respectively. What is the voltage amplification when the emitter current is 2 mA and current gain, \[\alpha =0.98\]?

    A)  9.8                             

    B)  98                

    C)  980                            

    D)  9800

    Correct Answer: C

    Solution :

     Emitter current is 2 mA, input resistance is \[400\,\,\Omega ,\] output resistance is \[400\,\,k\Omega =400\times {{10}^{3}}\Omega ,\] input voltage is \[2\times 400\,mV=800\,mV=0.800\,V\] and collector current \[{{I}_{C}}=0.98\times 2=1.96\,mA\]. Output or collector voltage is \[(1.96\times {{10}^{-3}})\times (400\times {{10}^{+3}})=784\,V\] Voltage amplification is, \[\frac{784}{0.800}=980\]


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