A) 15 m/s2, along positive x-axis
B) 15 m/s2, along negative x-axis
C) 1.5 m/s2, along negative x-axis
D) 1.5 m/s2, along positive x-axis
Correct Answer: C
Solution :
Here direction of velocity is changing after some time interval, ie, initial velocity and acceleration are in opposite sign \[{{a}_{av}}=\frac{({{\overrightarrow{v}}_{2}}-{{\overrightarrow{v}}_{1}})}{10}=\frac{(-5\hat{i}-10\hat{i})}{10}\]\[=-1.5\hat{i}\,m\text{/}{{s}^{2}}\] \[\Rightarrow \]\[1.5\,\text{m/}{{\text{s}}^{2}}\]along negative x-axis.You need to login to perform this action.
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