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JEE Main & Advanced Sample Paper JEE Main Sample Paper-42

  • question_answer
    Molar conductance of a 1.5M solution of an electrolyte is found to be 138.9 S cm2. The specific conductance of this solution is

    A)  0.208 S \[\text{c}{{\text{m}}^{-1}}\]        

    B)  0.102 S\[\text{c}{{\text{m}}^{-1}}\]

    C)  0.320 S \[\text{c}{{\text{m}}^{-1}}\]        

    D)  0.152 S \[\text{c}{{\text{m}}^{-1}}\]

    Correct Answer: A

    Solution :

    Molar conductance \[=\frac{\kappa \times 1000}{M}\] \[138.9=\frac{\kappa \times 1000}{1.5}\] \[\kappa =0.208S\,c{{m}^{-1}}\]


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