JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    Let \[f(x)={{(x-1)}^{2}}{{(x-2)}^{3}}{{e}^{x}}.\] Then

    A) f (x) has local maximum at x = 1

    B) f (x) has point of inflexion at x = 1

    C) f (x) has local minimum at x = 2

    D) all of these

    Correct Answer: A

    Solution :

    \[f(x)={{(x-1)}^{2}}{{(x-2)}^{3}}{{e}^{x}}\] \[\Rightarrow \]\[f'(x)=(x-1){{(x-2)}^{2}}({{x}^{2}}+2x-5){{e}^{x}}\]f(x) has local maximum at x = 1, since f'(x) changes from positive to negative. f(x) has a point of inflexion at x = 2.


You need to login to perform this action.
You will be redirected in 3 sec spinner