A) c = b/m
B) c = - bm
C) \[c=-b{{m}^{2}}\]
D) \[c=\frac{b}{{{m}^{2}}}\]
Correct Answer: C
Solution :
Solving \[y=mx+c\]with\[{{x}^{2}}=4\]by, we get. \[{{x}^{2}}=4b(mx+c)\Rightarrow {{x}^{2}}-4bmx-4bc=0\] Hence, discriminant = 0 \[\Rightarrow \]\[16{{b}^{2}}{{m}^{2}}+16bc=0\Rightarrow c=-b{{m}^{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
