JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    In a series resonant circuit, having L, C and R as its elements, the resonant current is i. The power dissipated in the circuit at resonance is

    A) \[\frac{{{i}^{2}}R}{\left( \omega L-\frac{l}{\omega C} \right)}\]

    B) zero

    C) \[{{i}^{2}}\omega L\]                     

    D) \[{{i}^{2}}R\]

    Correct Answer: D

    Solution :

    At resonance \[L\omega =\frac{1}{C\omega },\omega =\frac{1}{\sqrt{LC}}\] Current through circuit \[i=\frac{E}{R}\] Power dissipated at Resonance \[={{i}^{2}}R\]


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