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JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    A mixture of two gases X and Y is enclosed, at constant temperature. The relative molecular mass of X, which is diatomic, is 8 times that of Y which is monoatomic. What is the ratio of the r.m.s speed of molecules of Y to that of molecules of X?                                         

    A) 2                     

    B) 2Ö2

    C) 4                                 

    D) 8                     

    Correct Answer: B

    Solution :

    \[V=\sqrt{\frac{3RT}{M}}\Rightarrow \frac{{{V}_{x}}}{{{V}_{y}}}=\sqrt{\frac{{{M}_{y}}}{{{M}_{x}}}}\] \[\Rightarrow \]\[\frac{{{V}_{x}}}{{{V}_{y}}}=\sqrt{\frac{{{M}_{y}}}{8{{M}_{x}}}}\]\[\Rightarrow \]\[\frac{{{V}_{x}}}{{{V}_{y}}}=2\sqrt{2}\]


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