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JEE Main & Advanced Sample Paper JEE Main Sample Paper-40

  • question_answer
    A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm respectively and if 'C" has mol. wt of 2.0 what is the weight of 'C' in g present in the mixture.

    A) 8                                 

    B) 12

    C) 3                                 

    D) 6

    Correct Answer: B

    Solution :

    Total pressure of mixture of gases A,B & C = 10 atm. Partial pressure of A = (No. of moles of Ax 10)/10 or (No. of moles of A x10) / 10 = 3 Hence, no. of moles of A= 3 \[\therefore \]Partial pressure of B = (No. of moles of Bx10) /10 (since partial pressure of B=1 atm) \[\therefore \]No. of moles of B = 1 Now the no. of moles of C = 10 - (3+1) = 6; mole of C weighs = 2 gm. \[\therefore \]6 mole of C will weigh = 2 x 6 = 12


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