JEE Main & Advanced Sample Paper JEE Main Sample Paper-3

  • question_answer
    Statement-1: The domain of the function\[f(x)=\sqrt{{{\log }_{2}}\sin x}\]is \[(4n+1)\frac{\pi }{2},n\in N.\] Statement-1: Expression under even root should be\[\ge 0\]

    A)  Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

    B)  Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.

    C)  Statement-1 is true, Statement-2 is false.

    D)  Statement-1 is false, Statement-2 is true.

    Correct Answer: A

    Solution :

     For f(x) to be real log 2 (sin x ) \[\ge \]0 \[\Rightarrow \]\[\sin x\ge {{2}^{o}}\Rightarrow \sin x=1\] \[\Rightarrow \]\[x=(4n+1)\frac{\pi }{2},n\in N.\]


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