A) \[3\,\mu C\]
B) \[9\,\mu C\]
C) \[6\,\mu C\]
D) \[12\,\mu C\]
Correct Answer: B
Solution :
As \[{{\text{S}}_{\text{2}}}\] is open, hence \[{{\text{C}}_{1}}\And {{\text{C}}_{\text{3}}}\]are in series, also \[{{\text{C}}_{2}}\And \] \[{{\text{C}}_{4}}\]are in series combination. \[Q=\frac{3}{4}\times V=\frac{3}{4}\times 12=9\mu C;\]You need to login to perform this action.
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