A) \[{{\left( \frac{9}{16} \right)}^{6}}\]
B) \[{{\left( \frac{8}{15} \right)}^{7}}\]
C) \[{{\left( \frac{3}{5} \right)}^{7}}\]
D) none of these
Correct Answer: C
Solution :
n=7 Prob. of getting any no. out 1,2,3,... 9 is p = =9/15 \[\therefore \]q=6/5 \[P(x=7){{=}^{7}}{{C}_{7}}{{p}^{7}}{{q}^{0}}\] [Binomial distribution] \[={{\left( \frac{9}{15} \right)}^{7}}={{\left( \frac{3}{5} \right)}^{7}}\]You need to login to perform this action.
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