A) \[3\,\Omega \]
B) \[4\,\Omega \]
C) \[4/3\,\Omega \]
D) \[3/4\,\Omega \]
Correct Answer: C
Solution :
\[{{R}_{eq}}=\frac{{{R}_{1}}{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}\](Prallel) \[=\frac{4\times 2}{4+2}=\frac{8}{6}=\frac{4}{3}\Omega \]You need to login to perform this action.
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