question_answer

An organic compound is treated with \[NaN{{O}_{2}}\] and dil. \[HCl\]at \[{{0}^{o}}C\]. The resulting solution is added to an alkaline solution of \[\beta \] -naphthol where by a brilliant red dye is produced. It shows the presence of                                  

A)  \[-N{{O}_{2}}\] group         

B)  aromatic \[-N{{H}_{2}}\] group  

C)  \[-CON{{H}_{2}}\] group     

D)  aliphatic \[-N{{H}_{2}}\] group

Correct Answer: B

Solution :

 \[{{C}_{6}}{{H}_{5}}N{{H}_{2}}+NaN{{O}_{2}}+HCl\xrightarrow[{{0}^{o}}C]{}{{C}_{6}}{{H}_{5}}N=NCl\]