A) \[9x+10y-7=0\]
B) \[x-y+2=0\]
C) \[9x-10y+11=0\]
D) \[9x+10y+7=0\]
Correct Answer: C
Solution :
Given circles are\[{{x}^{2}}+{{y}^{2}}+4x-6y+9=0\] and\[{{x}^{2}}+{{y}^{2}}-5x+4y-2=0\] \[\therefore \]locus of centres is \[9x-10y+11=0\]You need to login to perform this action.
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