JEE Main & Advanced Sample Paper JEE Main Sample Paper-37

  • question_answer
    DIRECTIONS: Read the following passage and answer the questions that follows:
    A monoatomic ideal gas is filled in a no conducting container. The gas can be compressed by a movable no conducting piston. The gas is compressed slowly to 12.5% of its initial volume.
    The summation of work done by the gas and the change in the internal energy of the gas is

    A)  \[1\]                            

    B)  \[-1\]

    C)  \[\infty \]                     

    D)  \[0\]

    Correct Answer: D

    Solution :

     For adiabatic process \[dQ=0\] \[\therefore \] \[dU+dW=0\]


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