2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-36

  • question_answer
    A hydrogen-like atom has one electron revolving around a stationary nucleus. The energy required to excite the electron from the second orbit to the third orbit is\[47.2\text{ }eV\]. The atomic number of the atom is

    A)  3                    

    B)  4         

    C)  5                                

    D)  6

    Correct Answer: C

    Solution :

     \[E=\frac{13.6{{Z}^{2}}}{{{n}^{2}}};\] According to question, \[\frac{13.6{{Z}^{2}}}{4}-\frac{13.6{{Z}^{2}}}{9}=47.2\Rightarrow 13.6{{Z}^{2}}\left( \frac{5}{36} \right)=47.2\] \[\Rightarrow \] \[{{Z}^{2}}=25\Rightarrow Z=5\]


You need to login to perform this action.
You will be redirected in 3 sec spinner