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JEE Main & Advanced Sample Paper JEE Main Sample Paper-36

  • question_answer
    A proton, a deutron and an a particle accelerated through the same potential difference enter a region of uniform magnetic field, moving at right angles to B. What is the ratio of their K.E.?

    A)  \[1:2:2\]                       

    B)  \[2:2:1\]

    C)  \[1:2:1\]                       

    D)  \[1:1:2\]

    Correct Answer: D

    Solution :

     K.E. gained by charged particle of charge q when accelerated under a pot. diff. V will be \[{{E}_{k}}=qV;\]; For a given V, \[E\propto q\]. For proton, deutron and a-particle, the ratio of charges is \[1:1:2\].


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