A) \[20\sqrt{2}mA\]
B) \[20\,mA\]
C) \[40\,mA\]
D) \[80\,mA\]
Correct Answer: B
Solution :
\[{{X}_{C}}=\frac{1}{\omega C};\,{{E}_{rms}}=\frac{{{E}_{0}}}{\sqrt{2}};\] \[{{E}_{0}}=200\sqrt{2};\] \[{{E}_{rms}}=200;\] \[{{X}_{C}}=\frac{1}{\omega C}=\frac{1}{100\times {{10}^{-6}}}={{10}^{4}}\Omega \] \[V=IR\] or \[\frac{200}{{{10}^{4}}}I=20mA\]
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