question_answer

In the circuit shown, the total current supplied by the battery is

A)  2 ampere                     

B)  4 ampere

C)  1 ampere                     

D)  6 ampere

Correct Answer: B

Solution :

 \[6\Omega \] and \[2\Omega \]. are in parallel combination Hence, \[{{R}_{AB}}=\frac{6\times 2}{6+2}=1.5\Omega \] \[V=IR\Rightarrow \frac{60}{15}=I\Rightarrow I=4A\] \[[\because \,\,{{R}_{eq}}=\frac{3\times 3}{3+3}=\frac{9}{6}=1.5\,\Omega ]\]