A) \[0.55\,m\]
B) \[55\,m\]
C) \[5.5\,m\]
D) \[55\,\times {{10}^{-4}}m\]
Correct Answer: A
Solution :
Time taken in travelling horizontal distance of \[200\,m\]with constant velocity of \[600m/s\] is equal to \[200/600=1/3\text{ }sec.\]Vertical distance moved under acceleration due to gravity, with zero initial velocity will be \[S=ut+\frac{1}{2}a{{t}^{2}}=0+\frac{1}{2}\times 10\times {{(1/3)}^{2}}=0.55m.\]. Hence, the bullet should be aimed \[0.55m\] higher than target.
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