question_answer

\[{{C}_{6}}{{H}_{5}}MgBr\xrightarrow{Ether}A\xrightarrow{{{H}_{3}}{{O}^{+}}}Ba\]

A)           

B)  

C)          

D)  

Correct Answer: A

Solution :

 Alkyl or Aryl cyanide react with grignard reagent to form ketones  \[+{{C}_{6}}{{H}_{5}}MgBr\xrightarrow{Ether}\] \[{{C}_{6}}{{H}_{{{5}^{-}}}}\underset{{{C}_{6}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=NMgBr\xrightarrow{{{H}_{3}}{{O}^{+}}}\] or \[{{C}_{6}}{{H}_{5}}-\underset{{{C}_{6}}{{H}_{5}}}{\mathop{\underset{|}{\mathop{C}}\,}}\,=O+MgBrN{{H}_{2}}\]