A) \[1.7\times {{10}^{-6}}{{m}^{3}}\]
B) \[1.73\times {{10}^{-6}}{{m}^{3}}\]
C) \[1.70\times {{10}^{-6}}{{m}^{3}}\]
D) \[1.732\times {{10}^{-6}}{{m}^{3}}\]
Correct Answer: A
Solution :
\[V={{L}^{3}}\,={{(1.2+{{10}^{-2}}\,m)}^{3}}\] \[=1.728\times {{10}^{-6}}\,{{m}^{3}}\] Volume will have two significant figures because length has only two significant figure. So, \[V=1.7\times {{10}^{-6}}\,{{m}^{3}}\]
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