A) \[20\mu A\]
B) \[26\mu A\]
C) \[30\mu A\]
D) \[35\mu A\]
Correct Answer: B
Solution :
\[{{I}_{C}}\,=\frac{0.5}{800}\,=\frac{5}{8}\times {{10}^{-3}}A\] \[\,\alpha =\frac{{{I}_{C}}}{{{I}_{E}}}\] \[{{I}_{B}}+{{I}_{C}}={{I}_{E}}\] \[{{I}_{B}}={{I}_{E}}-\frac{{{I}_{C}}}{\alpha }\] \[=\frac{5}{8}\times {{10}^{-3}}\left( 1-\frac{1}{0.96} \right)\] \[=26\,\mu A\]
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