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JEE Main & Advanced Sample Paper JEE Main Sample Paper-33

  • question_answer
    A \[4\mu F\] capacitor is charged to 400V and then its plates are joined through a resistor. The heat produced in the resistor is:

    A)  \[0.64J~\]     

    B)                                     \[0.32\text{ }J\]

    C)  \[0.16J\]

    D)                     \[1.28J\]

    Correct Answer: B

    Solution :

    heat = energy loss in capacitor= (1 /2)CV2


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