question_answer

In the formation of \[HBr\] from \[{{H}_{2}}\] & \[B{{r}_{2}}\], following mechanism is observed.

[1] \[B{{r}_{2}}2Br\centerdot \]Equilibrium step

[2] \[{{H}_{2}}+Br\centerdot \xrightarrow{{}}HBr+H\centerdot \]Slow step

[3]\[H\centerdot +B{{r}_{2}}\xrightarrow{{}}HBr+Br\centerdot \] Fast step

Calculate the rate of reaction, if concentration of hydrogen is twice that of bromine and the rate constant is equal to \[I{{M}^{-1/2}}Se{{c}^{-1}}\]. Concentration of bromine is 1M.

A) \[2M\,Se{{c}^{-1}}\] 

B)     \[3M\,Se{{c}^{-1}}\]

C) \[4M\,Se{{c}^{-1}}\]        

D)    \[5M\,Se{{c}^{-1}}\]