A) 340min
B) 12min
C) 36 min
D) 40min
Correct Answer: C
Solution :
Energy of 1 mol of photon \[=\frac{{{N}_{A}}hc}{\lambda }\] \[=\frac{6.023\,\times {{10}^{23}}\,\times 6.62\,\times {{10}^{-34}}\,\times 3\,\times {{10}^{8}}}{560\,\times {{10}^{-9}}}\] \[=213.69\,\times {{10}^{3}}J\] \[=\frac{213\,.6\,\times {{10}^{3}}J}{100\,J{{s}^{-1}}}\,=2136\,s\cong \,36\,\min \].
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