A) \[1,2\]
B) \[1,-2\]
C) \[-1,1\]
D) \[-1,-2\]
Correct Answer: C
Solution :
Put\[\Delta =0\] \[\Rightarrow \left| \begin{matrix} k & 1 & 1 \\ 1 & -k & 1 \\ 1 & 1 & 1 \\ \end{matrix} \right|=0\Rightarrow {{k}^{2}}=1\Rightarrow k=\pm 1\]
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