| Expt. Initial concentration | Initial rate of formation of D (Mol \[L-1\] \[Mi{{n}^{-1}}\]) | ||
| 1 | \[0.1\] | \[0.1\] | \[6.0\times {{10}^{-3}}\] |
| 2 | \[0.3\] | \[0.2\] | \[7.2\times {{10}^{-1}}\] |
| 3 | \[0.3\] | \[0.4\] | \[2.88\times {{10}^{-1}}\] |
| 4 | \[0.4\] | \[0.1\] | \[2.4\times {{10}^{-2}}\] |
A) Rate \[=k[A]\,\,[B]\]
B) Rate \[=k[A]\,\,{{[B]}^{2}}\]
C) Rate \[=k{{[A]}^{2}}\,\,{{[B]}^{2}}\]
D) Rate \[=k{{[A]}^{2}}\,\,[B]\]
Correct Answer: B
Solution :
\[r=k{{[A]}^{x}}{{[B]}^{y}}\] \[6.0\times {{10}^{-3}}=K{{(0.1)}^{x}}{{(0.1)}^{y}}\]?[a] \[2.4\times {{10}^{-2}}=K{{(0.1)}^{x}}{{(0.1)}^{y}}\] ?[b] [b] / [a] gives x = 1 \[7.2\times {{10}^{-2}}=K{{(0.3)}^{x}}{{(0.2)}^{y}}\] ?[c] \[2.88\times {{10}^{-1}}=K{{(0.3)}^{x}}{{(0.4)}^{y}}\] ?[d] [d] / [c] gives y = 2.
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