A) \[\frac{7}{45}\]
B) \[\frac{13}{45}\]
C) \[\frac{11}{18}\]
D) \[\frac{1}{2}\]
Correct Answer: B
Solution :
Required probability \[=\frac{(5\times 3)+(4\times 2)+(3\times 1)}{{}^{6}{{C}_{2}}\times {}^{4}{{C}_{2}}}=\frac{13}{45}\]
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