A) \[N{{O}_{2}}\]
B) \[{{N}_{2}}{{O}_{4}}\]
C) \[{{N}_{2}}{{O}_{3}}\]
D) \[{{O}_{2}}\]
Correct Answer: D
Solution :
\[2O{{H}^{-}}-2{{e}^{-}}\xrightarrow{\,}\,2OH\xrightarrow{\,}\,{{H}_{2}}O+\frac{1}{2}{{O}_{2}}\]
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