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JEE Main & Advanced Sample Paper JEE Main Sample Paper-2

  • question_answer
    A particle of mass 4 gm lies in a potential field given by \[V=200{{x}^{2}}+150\,\text{ergs/gm}\]  The frequency of vibration is

    A)  \[1.6\,{{\sec }^{-1}}\]                   

    B)  \[0.25\,{{\sec }^{-1}}\]

    C)  \[200\,{{\sec }^{-1}}\]                  

    D)  \[3.2\,{{\sec }^{-1}}\]

    Correct Answer: D

    Solution :

    The potential energy of the system \[U=mV=4(200{{x}^{2}}+150)\] \[F=-\frac{dU}{dx}=-1600x\] \[\Rightarrow \,\,a=\frac{F}{m}=-400x\] Frequency of oscillation \[=\frac{\sqrt{400}}{2\pi }=3.2\,{{\sec }^{-1}}\]


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