JEE Main & Advanced Sample Paper JEE Main Sample Paper-29

  • question_answer
    At what temperature does the rms speed of gas molecules will be double the rms speed at NTP(Pressure is assumed constant):

    A) \[564\,K\]                           

    B) \[{{273}^{o}}C\]

    C) \[{{819}^{o}}C\]          

    D) \[{{1092}^{o}}C\]

    Correct Answer: C

    Solution :

    \[\Rightarrow \,{{m}^{4}}-2{{m}^{2}}\,+1=0\] for given gas                 \[\Rightarrow \,{{({{m}^{2}}-1)}^{2}}=0\,\Rightarrow m=\pm \,1\]                 Given \[\therefore \]                 \[x-y=\frac{3}{2}\]                 \[\therefore \]


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