A) zero
B) \[0.02\]
C) \[0.03\]
D) \[0.036\]
Correct Answer: B
Solution :
\[\therefore \,\Delta \ge 0\Rightarrow 81-72b\ge 0\Rightarrow b\le \frac{9}{8}\] is reverse biased. As it is an ideal diode, its resistance is infinite and no current flows through it. \[S=\frac{n}{2}\,[16+4(n-1)];\,\,T=\frac{n}{2}\,[34\,+2\,(n-1)\,]\] is forward biased. As it is an ideal diode, its resistance is zero and hence, the current through \[\therefore \,\,S-T=0\Rightarrow \,16+4n-4=34\,+2n-2\] resistor is: \[\Rightarrow \,\,4n+12=32+2n\]
You need to login to perform this action.
You will be redirected in
3 sec
