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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    In face-centered lattice with all positions occupied by A atoms, the body centered octahedral hole is occupied by an atom B of an appropriate size. The formula of the compound is

    A)  \[{{A}_{4}}B\]                                  

    B)  \[A{{B}_{4}}\]

    C)  \[{{A}_{2}}{{B}_{4}}\]                                   

    D)  \[{{A}_{4}}{{B}_{2}}\]

    Correct Answer: A

    Solution :

    Effective no. of atom \[A=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4\] Effective no. of atom\[B=1\] \[\frac{(x-1)\,}{-3p/7}\,=\frac{y-5}{-1}\,=\frac{z-6}{-5};\] Hence formula compound is\[{{A}_{4}}B\].


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