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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    A certain gas a hexamerised to a small extent. If PV initially 1 mole gas is taken, the ratio \[\frac{PV}{RT}\] will be equal to

    A)  \[1-\frac{5{{K}_{c}}}{{{V}^{5}}}\]                             

    B)  \[\frac{5{{K}_{c}}}{{{V}^{5}}}\]

    C)  \[1-\frac{5K_{c}^{2}}{{{V}^{5}}}\]                           

    D)  \[1-\frac{4K_{c}^{2}}{{{V}^{4}}}\]

    Correct Answer: A

    Solution :

    \[\frac{PV}{RT}=\]Total no. of moles of gases at equilibrium.


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