JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    The potential field of an electric field\[\vec{E}=(y\hat{i}+x\hat{j})\] is

    A)  \[V=-xy+\] constant

    B)  \[V=-(x+y)+\] constant

    C)  \[V=-({{x}^{2}}+{{y}^{2}})+\] constant

    D)  \[V=\] constant

    Correct Answer: A

    Solution :

    \[dV=\overrightarrow{E}.\overrightarrow{dr}\] \[=-(y\widehat{i}+x\widehat{j}).(dx\widehat{i}+dy\widehat{j}+dz\widehat{k})\] \[=-ydx-xdy=-d(xy)\] [because using product rule of differential operator\[d(xy)=dx\times y+x\times dy]\] on integration we get \[V=-xy+\]constant.


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