A) \[0.25\,m\]
B) \[0.8\,m\]
C) \[0.5\,m\]
D) \[1\,\,m\]
Correct Answer: C
Solution :
\[v=u+at\] \[0=7-2t\] \[t=3.5\] Hence velocity of the particle will be zero at \[3.5\,\,\sec \] Hence distance travelled between 3 to 3.5 sec will be same as distance travelled between3.5 to 4 sec due to symmetry of motion. \[S=\frac{1}{2}\times 2\times {{(0.5)}^{2}}=0.25\,\,m\] Hence distance travelled in fourth second will be\[2\times 0.25=0.5\,\,m\]You need to login to perform this action.
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