A) 4
B) 2
C) 18
D) 6
Correct Answer: A
Solution :
\[[W]=M{{L}^{2}}{{T}^{-2}}\] In new system: 1 unit work \[=\frac{(1unit\,\,mass){{(1unit\,\,length)}^{2}}}{{{(1unit\,\,time)}^{2}}}\] \[=\frac{9kg{{(2m)}^{2}}}{{{(3\sec )}^{2}}}=4\frac{kg{{m}^{2}}}{{{\sec }^{2}}}=4J\]You need to login to perform this action.
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