A) \[[{{H}^{+}}]\] from \[HA>[{{H}^{+}}]\] form HB
B) \[HA\,\alpha >\alpha \] of HB
C) \[[A-]>[{{B}^{-}}]\]
D) \[[HA]>[HB]\]
Correct Answer: D
Solution :
\[HA\rightleftharpoons {{H}^{+}}+{{A}^{-}}\,\,\,\,\,\,\,\,\,\,{{K}_{{{a}_{1}}}}\] \[HA\rightleftharpoons {{H}^{+}}+{{A}^{-}}\,\,\,\,\,\,\,\,\,\,{{K}_{{{a}_{2}}}}\] \[\alpha =\sqrt{\frac{{{K}_{a}}}{C}}\] \[\frac{{{\alpha }_{1}}}{{{\alpha }_{2}}}\,=\sqrt{\frac{{{K}_{{{a}_{1}}}}}{{{K}_{{{a}_{2}}}}}}\] as \[{{K}_{{{a}_{1}}}}>{{K}_{{{a}_{2}}}};\,\,{{\alpha }_{1}}>{{\alpha }_{2}}\] So, \[[HA]<[HB]\]
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