JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    The locus of the foot of the perpendiculars drawn from the vertex on a variable tangent to the parabola \[{{y}^{2}}=4ax\] is

    A)  \[x({{x}^{2}}+{{y}^{2}})=a{{y}^{2}}=0\]           

    B)  \[y({{x}^{2}}+{{y}^{2}})=a{{x}^{2}}=0\]

    C)  \[x({{x}^{2}}-{{y}^{2}})+a{{y}^{2}}=0\]

    D)  \[{{x}^{2}}+{{y}^{2}}+a{{y}^{2}}=0\]

    Correct Answer: A

    Solution :

    Tangent \[y=mx+\frac{a}{m}\] Line through origin and perpendicular to it is x + my = 0 = 0. Now eliminate m.


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