JEE Main & Advanced Sample Paper JEE Main Sample Paper-24

  • question_answer
    The equation to the locus of the middle point of the portion of the tangent to the ellipse \[\frac{{{x}^{2}}}{16}+\frac{{{y}^{2}}}{9}=1\] included between the co-ordinate axes is the curve

    A)  \[9{{x}^{2}}+16{{y}^{2}}=4{{x}^{2}}{{y}^{2}}\]         

    B)  \[16{{x}^{2}}+9{{y}^{2}}=4{{x}^{2}}{{y}^{2}}\]

    C)  \[3{{x}^{2}}+4{{y}^{2}}=4{{x}^{2}}{{y}^{2}}\]          

    D)  \[9{{x}^{2}}+16{{y}^{2}}={{x}^{2}}{{y}^{2}}\]

    Correct Answer: A

    Solution :

    \[9{{x}^{2}}+16{{y}^{2}}=4{{x}^{2}}{{y}^{2}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner