JEE Main & Advanced Sample Paper JEE Main Sample Paper-23

  • question_answer
    Ionisation constant \[({{K}_{a}})\] of weak acid (HA) in terms of \[\wedge \,_{m}^{\infty }\] and \[\wedge {{\,}_{m}}\] is

    A)  \[{{K}_{a}}=\frac{C\wedge _{m}^{\infty }}{\left( {{\wedge }_{m}}-\wedge _{m}^{\infty } \right)}\]      

    B)  \[{{K}_{a}}=\frac{C\wedge _{m}^{2}}{\wedge _{m}^{\infty }\left( \wedge _{m}^{\infty }-{{\wedge }_{m}} \right)}\]

    C)  \[{{K}_{a}}=\frac{C{{\left( \wedge _{m}^{\infty } \right)}^{2}}}{\wedge _{m}^{\infty }\left( \wedge _{m}^{\infty }-{{\wedge }_{m}} \right)}\]

    D)  Data Insufficient

    Correct Answer: B

    Solution :

    \[{{K}_{a}}=\frac{C{{\alpha }^{2}}}{1-\alpha }\]                    \[\alpha =\frac{{{\Delta }_{m}}}{\Delta _{m}^{\infty }}\]


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