A) \[0.5\,A{{s}^{-1}}\]
B) \[2.0\,A{{s}^{-1}}\]
C) \[2.5\,A{{s}^{-1}}\]
D) \[0.25\,A{{s}^{-1}}\]
Correct Answer: C
Solution :
\[i={{i}_{0}}\left( 1-{{e}^{-\frac{Rt}{L}}} \right)\] \[\frac{di}{dt}\,=\frac{d}{dt}\,{{i}_{0}}\,-\frac{d}{dt}\,\left( {{i}_{0}}{{e}^{-\frac{Rt}{L}}} \right)=0+\frac{{{i}_{0}}R}{L}{{e}^{\frac{-Rt}{L}}}\] Initially \[t=0\] \[\Rightarrow \,\frac{di}{dt}=\,\frac{{{i}_{0}}\times R}{L}=\frac{E}{L}=\frac{5}{2}\,=2.5\,A{{s}^{-1}}\]
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