A) \[0.6\]
B) \[0.4\]
C) \[0.2\]
D) zero
Correct Answer: D
Solution :
Volume of cylindrical wire \[V=\frac{\pi {{x}^{2}}L}{4}\] ?(i) where, x is the diameter of wire Taking log and then applying differential operator in both side of equation (i) we get \[\frac{\Delta V}{V}\,=\frac{2\Delta r}{r}+\frac{\Delta l}{l}\] \[=2\left( -0.5\,\frac{\Delta l}{l} \right)\,+\frac{\Delta l}{l}\] \[\because \,\,-\frac{\Delta r}{r}\,=0\frac{\Delta l}{l}=0\] Hence percentage change in volume = 0
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